Physics, asked by puru866, 1 year ago

let A=i+j and B=2i-j. Magnitude of a copalner vector C such that A.C=BC=AB is given by​

Answers

Answered by sonuvuce
4

The magnitude of coplanar vector C is √5/3

Explanation:

Given:

\vec A=\hat i+\hat j

\vec B=2\hat i-\hat j

To find out:

A coplanar vector \vec C

Such that

\vec A.\vec C=\vec B.\vec C=\vec A.\vec B

Solution:

Let the vector C be

\vec C=x\hat i+y\hat j

\vec A.\vec B=(\hat i+\hat j).(2\hat i-\hat j)=2-1=1

Thus,

\vec A.\vec C=\vec B.\vec C=1

\vec A.\vec C=(\hat i+\hat j).(x\hat i+y\hat j)

\implies x+y=1

Similarly

\vec B.\vec C=(2\hat i-\hat j).(x\hat i+y\hat j)

\implies 2x-y=1

Adding both the equations

3x=2

\implies x=\frac{2}{3}

Therefore,

y=1-x=1-\frac{2}{3}=\frac{1}{3}

Thus, the vector \vec C is

\vec C=\frac{2\hat i+\hat j}{3}

The magnitude of \vec C is

|\vec C|=\frac{1}{3}(\sqrt{2^2+1^2})

\implies |\vec C|=\frac{\sqrt{5}}{3}

Hope this answer is helpful.

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Answered by rahulramwn4647
0

there is no problem to this question so surely correct this question

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