Question

let a=sin 42° b=cos 52°c=sin 67° then find correct order​

Answer 1

Order : b. a. c

Step-by-step explanation:

a and c are in terms of sin

b is in terms of cos

so convert the b in terms of cos

cosB=sin(90-B) where B=52

sin(90-52)=sin38

so now the modified problem is

a=sin 42

b=sin 38

c=sin 67

In sin terms ,value increases as we move 0 to 90

so the order is

sin 38, sin 42, sin 67

b,a,c

I hope this will help you

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