Question

Let a1 , a2 , a3 , a4 , a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3 . If the sum of the numbers in th

Answer 1

A sequence of 5 consecutive odd numbers is:

a1, a2, a3, a4, a5.

A new sequence of 5 consecutive even numbers is ending with 2a3:

2a3 - 8,  2a3 - 6,  2a3 - 4, 2a3 - 2,  2a3   ( d = 2, same as the first sequence )

The sum of the numbers in the second sequence is 450

2a3 - 8 + 2a3 - 6 + 2a3 - 4 + 2a3 - 2 + 2a3 = 450

10 a3 - 20 = 450

10 a3 = 450 + 20

10 a3 = 470

a3 = 470 : 10 = 47

a5 = 47 + 2 * 2 = 47 + 4 = 51

Answer:  a5 = 51