Question

Let a1, a2, a3, a4... be consecutive odd natural numbers. Find the 33rd term of the following series. Avg(a1,a2,a3,a4,a5), Avg(a4,a5,a6,a7,a8), Avg(a7,a8,a9,a10,a11)...., Where Avg(a,b,c,d,e) is the average function and Avg(a1,a2,a3,a4,a5) = 113.

Answer 1

Answer:

a33 =a1+ 32(a2-a1)

Step-by-step explanation:

a1=a1

d=a2-a1

a33=a+32d

a33=a1+ 32(a2-a1)