Question

Let ab5c be all four-digit multipliers of number 36 with distinct digits. how many numbers satisfy given conditions.​

Answer 1

Answer:

Smallest and largest 3 digit number multiplied by 9 are 108 and 999

By AP

a=108 a

n

=999 d=9 n=?

999=108+(n−1)9

n=100.

Answer 2

Answer:

There are actually 8 of them. Those are 3456, 3852, 4356, 4752, 7452, 7956, 8352, and 9756. I hope this helps!

Step-by-step explanation:

There are actually 8 of them. Those are 3456, 3852, 4356, 4752, 7452, 7956, 8352, and 9756. I hope this helps!