let abc and def be similar triangles and their area be 64 cm square and 121 cmsquare respectively. if Ef=15.4 cm then bc=
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b) 11.2 is the correct
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please mark as brainliest answer
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the answer is option B
ar(ABC)/ar(DEF) = BC square / EF square
64/121= 15.4^2/EF^2
square rooting both sides, we get
8/11=15.4/EF
EF=11.2
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