Normal water contains isotope of hydrogen 3h, tritium. it has a half-life of 12.3 years. determine the age of a bottle of wine whose 3h radiations is about 1/10 that present in new wine.
Answers
Answered by
0
please ask the question on Google or internet that we can not be have these questions and answers
Answered by
0
Hey dear,
● Answer -
Age = 40.87 years
● Explaination -
# Given -
Let T be half life of tritium.
T = 12.3 years
A/A0 = 1/10
# Solution -
Equation of radioactivity -
A = A0 × 2^(-t/T)
Solving this for t,
t = T/0.693 ln(A0/A)
t = 12.3 / 0.693 × ln(10)
t = 17.75 × 2.303
t = 40.87 years
Therefore, the age of given bottle of wine is 40.87 years.
Hope this help you...
● Answer -
Age = 40.87 years
● Explaination -
# Given -
Let T be half life of tritium.
T = 12.3 years
A/A0 = 1/10
# Solution -
Equation of radioactivity -
A = A0 × 2^(-t/T)
Solving this for t,
t = T/0.693 ln(A0/A)
t = 12.3 / 0.693 × ln(10)
t = 17.75 × 2.303
t = 40.87 years
Therefore, the age of given bottle of wine is 40.87 years.
Hope this help you...
Similar questions
India Languages,
8 months ago
English,
8 months ago
Political Science,
1 year ago
Accountancy,
1 year ago
Math,
1 year ago
Geography,
1 year ago