Let ABC be a triangle such that AB=6√3cm, AC=12cm, and BC=6cm. Angle B =?
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Answer:
In ABC,
AC²=(12)²=144cm² ---equation 1
AB²+BC²=(6√3)²+(6)²=108+36=144cm². --equation 2
From, the equation 1 and 2 we have,
AC²=AB²+BC²
Then, by the Pythagoras theorem angle B=90°
Step-by-step explanation:
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