let ABC be an equilateral triangle in which co-ordinate of B and C are (5,0) and (-5,0) respectively. find the co-ordinates of A
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Answered by
5
Answer:
Step-by-step explanation:
length a = 5 - (-5) =10
height of triangle =√( 10^2 - 5^2) =√75 =5√3
so co ordinate of A = (0,5√3)
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jasmeenkaur072004:
plzz can you tell me clearly
Answered by
4
Answer:
length = 5-(-5)=10
Height of triangle = root 10²-5²
= root 75
=5 root 3
coordinates of A=(0,5root 3)
Step-by-step explanation:
ABC equilateral triangle coordinates of Band C are (5,0), and (-5,0) . coordinates point of the point A. equilateral triangle 3 side equal 3 side equal digit 10
solution:
root 10² -5²
root 75
0,5 root 3
Attachments:
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