let ∆ABC ~∆DEF and their area's be respectively 10 and 28 cm BC = 2.3 cm so what is EF=?
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As ∆ABC~∆DEF
ar(∆ABC) BC×BC
---------------- =---------------
ar(∆DEF) EF×EF
10. 2.3 × 2.3
---------- = ------------------
28. EF × EF
EF ×EF ×10= 2.3×2.3×28
148.12
EF×EF. = --------------
10
EF×EF = 14.812
EF. = 3.8 cm
ar(∆ABC) BC×BC
---------------- =---------------
ar(∆DEF) EF×EF
10. 2.3 × 2.3
---------- = ------------------
28. EF × EF
EF ×EF ×10= 2.3×2.3×28
148.12
EF×EF. = --------------
10
EF×EF = 14.812
EF. = 3.8 cm
davina46:
thanks for the trues!
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