Question

let ABC is right angled triangle in which angle B =90 degree AC =13cm and AB=12cm find the value of sec c​

Answer 1

Answer:

answer is AC=18 cm

Step-by-step explanation:

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Answer 2

Concept: This is the question of Trigonometry. In a Right-angled triangle, the hypotenuse is the largest side of a triangle, and the relation between the base and perpendicular is given by

$(hypotenuse)^{2} = (base)^{2} + (perpendicular)^{2}$

& Sec C = $\frac{1}{Cos C}$ = $= \frac{hypotenuse}{Base}$

Given: ΔABC is a right angled triangle, B= 90°, AC= 13 cm, AB=12cm

To find: Value of Sec C

Solution:

$BC^{2}$= $AC^{2} - AB^{2}$

      = $13^{2} - 12^{2}$

      = 169 - 144

      = 25

BC= $\sqrt{25}$

    = 5 Cm

   now Sec C = $\frac{AC}{BC}$

                      = $\frac{13}{5}$ Cm

Hence the value of Sec C is $\frac{13}{5}$