Question

Let an amount of Rs. 47, 000 be divided into three
parts such that three times the first is equal to four times
the second and five times the third. Find the difference
between the largest and the smallest parts.
​

Answer 1

Step-by-step explanation:

let there be three parts A,B and C

A.T.Q 3A=4B or A/B= 4/3......eq 1

also 3A=5C or A/C = 5/3.......eq2

multiply eq1 by 5/4 in each term make value of A equal in both eq 1 and eq2

A/B=4×5/4/3×5/4=5/3.75.....eq3

so from eq2 and eq3

we get A/B/C=5/3.75/3

let parts be 5x,3.75x and 3x

total parts 11.75x=47000

x=4000

difference between the largest and the smallest parts i.e 5x-3x=2x =2×4000= 8000

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