Question

let an be an arithmetic progression.if a1=4 and a2=7, determine a11

Answer 1

Answer:

a11 = 34

Step-by-step explanation:

Please refer to the attachment given below :

Answer 2

Given,

a1= 4

a2 = 7

To Find,

a11=?

Solution,

We know from the formula of the nth term in AP that $a_n = a +(n-1)d$

a = a1 = 4  [Given]

$a_2 = a + (2-1)d$

$7 = 4 + 1d$ [Putting values of a1 and a2]

d = 7 - 4 = 3

Common difference(d) = 3

For 11th term of AP,

$a_{11} = 4 +(11-1)3$

$a_{11} = 4 +10*3$

$a_{11} = 4 + 30$

$a_{11} = 34$

Hence, a11 term of this AP is 34