Question

Let An be the area enclosed by the nth orbit in a hydrogen atom. The graph of ln (An/A1) against ln(n)
(a) will pass through the origin
(b) will be a straight line with slope 4
(c) will be a monotonically increasing nonlinear curve
(d) will be a circle

Answer 1

Answer:

please write correct question

Answer 2

The graph in $\left(\frac{A n}{A 1}\right)$ against in(n) a) will pass through the origin and b) will be straight line with slope 4.

Explanation:

From the above derivation we can clearly see that the graph is a straight line and will be passing through the origin and will have a s.

$A_{n}=\pi r_{n}^{2}=\pi\left(a_{0} n^{2}\right)^{2}=\pi a_{0}^{2} n^{4}$

$\text { Or } \frac{A_{n}}{A_{1}}=n^{4}$

$\text { or } \ln \left(\frac{\mathrm{A}_{\mathrm{n}}}{\mathrm{A}_{1}}\right)=4 \ln \mathrm{n}$

$Hence, the graph of \ln \left(\frac{\mathrm{A}_{\mathrm{n}}}{\mathrm{A}_{\mathrm{l}}}\right) against in n is a straight line passing through the origin and have a slope of 4 .$