Let An be the area enclosed by the nth orbit in a hydrogen atom. The graph of ln (An/A1) against ln(n)
(a) will pass through the origin
(b) will be a straight line with slope 4
(c) will be a monotonically increasing nonlinear curve
(d) will be a circle
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The graph in against in(n) a) will pass through the origin and b) will be straight line with slope 4.
Explanation:
From the above derivation we can clearly see that the graph is a straight line and will be passing through the origin and will have a s.
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