Question

let c/5=f-32/9.if c lies between 10 and 20,then​

Answer 1

Let (C/5) = (F - 32/9). If C lies between 10 and 20, then :

Given : C5=F−329 and 10<C<20

⇒C=5F−(32)59

Since, 10<C<20

⇒10<5F−1609<20

⇒90<5F−160<180

⇒90+160<5F<180+160

⇒250<5F<340

⇒2505<F<3405

⇒50<F<68  

mrk me as brainliest plzz