Question

Let →C=→A+→B
(a) | →C | is always greater than | →A |
(b) It is possible to have | →C | < | →A | and | →C | < | →B |
(c) C is always equal to A + B
(d) C is never equal to A + B.

Answer 1

Explanation:

• When $\rightarrow C=\rightarrow B+\rightarrow A$, then there is a possibility to have $A \rightarrow>C \rightarrow$ and $B \rightarrow>C \rightarrow$

• When $C \rightarrow=B \rightarrow+A \rightarrow$, the statements $|\rightarrow C|$ is always greater than $|\rightarrow A|$ , $C$is never equal to $A+B$ and C is always equal to $A+B$ are incorrect.  

• Here, the resultant vector’s magnitude could or could not be less or equal than the $A \rightarrow$ and $B \rightarrow^{\prime} s$ magnitudes or the sum of both vectors’ magnitudes when they are in opposite directions.  

Answer 2

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