let d be the HCF of 24 and 36 Find two numbers A and B such that d is equal to 24a + 36 b
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24 = 2³ × 3
36 = 2² × 3²
HCF (24,36) = 4 × 3 = 12 ,
12 = 24a + 36b
12 = (-1)× 24 + 36 × 1
So, a = -1 and b = 1
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