let f:[-1,1]->R defined by f(x)=x/x+2, show that f is 1-1. find f' for the function f[-1,1]-> range (f)
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(Hint: For y ∈ Range f, y = , for some x in [ - 1, 1], i.e., ) It is clear that f: [ - 1, 1] → Range f is onto. ∴ f: [ - 1, 1]→ Range f is one-one and onto and therefore, the inverse of the function: ... Let g: Range f → [ - 1, 1] be the inverse of f.
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