Question

Let f={(1,3),(-1,1),(0,2)) be a function defined by f (x)= ax+b for some integer a,b then the value of b is​

Answer 1

Step-by-step explanation:

={(1,1),(2,3),(0,−1),(−1,−3)}

f(x)=ax+b

(1,1)f

⇒f(1)=1

⇒a×1+b=1

⇒a+b=1    

(0,−1)∈f

⇒f(0)=−1

⇒a×0+b=−1

⇒b=−1

On substituting b=−1 in eqn (1), we get

a+(−1)=1

⇒a=1+1=2

Thus the respective values of a and b are 2 and −1