Question

Let f : ℝ → ℝ and g : ℝ → ℝ are given by f(x) = cosx and g(x) = 3x^2
(a) Find g0f

(b) Show that g0f ≠ fog.​

Answer 1

Answer:g0f=cosx

Pls mark it as the brainlest answer

Step-by-step explanation:

Answer 2

Answer : Given : f(x)=cosx and g(x)=3x^2

a. gof = g{f(x)} = g(cosx) =3(cosx)^2=3cos^2x

b. fog = f{g(x)} = f(3x^2) = cos3x^2

now clearly gof is not equal to fog.

Hope it will help you.

Thank you.