Let f be a function defined on (0,2),then the function g(x)=f(9x-1) has domain
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if f=0
then
g[x] = 0*[9x-1]
= 0x -0
∴ x=0
if f= 2
then
g[x] = 2*[9x-1}
18x-2=0
18x=2
x=1/9
then
g[x] = 0*[9x-1]
= 0x -0
∴ x=0
if f= 2
then
g[x] = 2*[9x-1}
18x-2=0
18x=2
x=1/9
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