Question

The adjacent angles of a parallelogram are (3x-12) and (52+2x). Find the angles of the parallelogram?

Answer 1

sum of adjacent angle of triangle=180degree.
(3x-12)+(52+2x)=180 degree
5x+40=180degree
5x=180-40
5x=140
x=140/5
=28
so
(3x-12)=3*28-12=72
52+2x=52+2*28=108
hope its help

Answer 2

sum of adjacent angles=180

(3x-12) +(52+2x) = 180

3x-12 + 52 + 2x = 180
5x= 180 -52 + 12
5x= 192 - 52
x=140/5=28
x=28


then ,3x-12=3×28-12

84-12=82

so second angle is also 82

and,52 +2x=52+2×28
52+56 =108

so next angle is also108