Physics, asked by rajeswarigangireddy4, 6 hours ago

Let F be the force acting on a particle having position vector i and 7 be the torque of this force about the origin. Then:​

Answers

Answered by yashwanth575859
0

Explanation:

torgue is the cross product of the force F and the position vector'r'

τ=r×F

so the angle betweenτ and F is 90

0

and between τ and r is 90

0

for example if we take dot product between two vectors as θ=90

0

⟹cosθ=cos90

0

=0 ⟹r.τ=0

F.τ=0

Answered by BRAINLY1OFFICIAL
0

Answer:

Explanation:

First we will know what force is. Force is any interaction that can change the motion of an object. It can cause any object with mass to change its motion. Force can also be described as push or a pull. Force is a vector quantity (i.e. it has both magnitude as well as direction). SI unit of force is newton (N).

Now we will know about Torque. Another name of torque is moment of force. Torque or moment of force is the tendency of a force to rotate or orient an object about an axis, fulcrum, or pivot. Just as force is a push or a pull, a torque can be thought of as a twist to any object. Torque is denoted by τ. Torque is also a vector quantity and its SI units are newton meters (Nm). Torque is the cross product of the force and the position vector τ→=r→×F→. Here torque is acting about the origin so the angle between r→ and τ→ is 90∘ and between F→ and τ→ is also 90∘.

Now when we take dot product of two vectors r→ and τ→ as θ=90∘ we get

r→⋅τ→=rτcos90∘

⇒r→⋅τ→=0

∴r⋅τ=0

Similarly when we take dot product ofF→ and τ→, as θ=90∘ we get

F→⋅τ→=Fτcos90∘

⇒F→⋅τ→=0

∴F⋅τ=0

Hence, the correct answer is option D.

Note: Torque due to a force is more if the distance between the point of application of force and the point about which the body rotates is more. If the distance at which force is applied is more from the fulcrum then a lesser amount of force is required to produce the same torque.

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