Question

Let f:R→R be defined by f(x)={2x:x>3x2:1<1x≤33x:x≤1 Thenf(−1)+f(2)+f(4)is

Answer 1

Answer:

9

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Step-by-step explanation:

As -1 ≤ 1, the third rule applies for f(-1).  Thus f(-1) = 3 × (-1) = -3.

As 1 < 2 ≤ 3, the second rule applies for f(2).  Thus f(2) = 2² = 4.

As 4 > 3, the first rule applies for f(4).  Thus f(4) = 2 × 4 = 8.

So f(-1) + f(2) + f(4)

= 3×(-1) + 2² + 2×4

= -3 + 4 + 8

= 9