Math, asked by sitharasinan4319, 1 year ago

Let f(x)=81+3e−0.7x .What is the value of f(3) ?Round the answer to the nearest hundredth.Enter your answer in the box.

Answers

Answered by payal48200232
6
Hi friend here is your answer
f(x)=81+3e-0.7x
f(2)=81+3e-0.7(2)
f(2)=81+3e-1.4
f(2)=79.6+3e
I hope it helps you
Answered by SocioMetricStar
11

Answer:

The value of f(3) is 81.37

Step-by-step explanation:

The given function is

f(x)=81+3e^{-0.7x}

In order to find the value of f(3), substitute x = 3 in above function.

f(3)=81+3e^{-0.7(3)}

The exponent -0.7(3)= -2.1

f(3)=81+3e^{-2.1}

The value of e^(-2.1) = 0.122456

f(3)=81+3(0.122456)

On simplifying, we get

f(3)=81.367368

In nearest hundredth, the value becomes

f(3)=81.37

Therefore, the value of f(3) is 81.37

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