Let f(x) = ax2 + bx + c, where a,b and c are certain constants and a≠0. It is known that f (5) = -3f(2) and that 3 is a root of f(x) = 0. 21. What is the other root of f(x) = 0?
Answers
Answer:
Step-by-step explanation:
: ax^2+bx+c=k [x^2 -(α+β)x+αβ]
Equating co-efficient of x^2, x & constant terms on both sides, we get
a = k . . . . . . . . . . . . . .(1)
b = -k(α+β) . . . . . . . . . . . . . .(2)
c = kαβ . . . . . . . . . . . . . .(3)
Putting k=a in (2) & (3) we get
b= -a(α+β) & c = aαβ
∴ α+β = - b/a & αβ = c/a
Thus if α, β are zeroes of the quadratic polynomial ax^2+bx+c, a≠0 then
Sum of zeroes = α+β = -b/a = - (coefficient of x)/(coefficient of x^2 )