Question

Let f(x) = logₑ(sinx), (0 < x < π) and g(x) = sin⁻¹(e⁻ˣ), (x ≥ 0). If α is a positive real number such that a = (fog)’(α) and b = (fog)(α), then
(A) aα² + bα – a = 2α²
(B) aα² – bα – a = 0
(C) aα² – bα – a = 1
(D) aα² + bα + a = 0

Answer 1

Step-by-step explanation:

Let f(x) = logₑ(sinx), (0 < x < π) and g(x) = sin⁻¹(e⁻ˣ), (x ≥ 0). If α is a positive real number such that a = (fog)’(α) and b = (fog)(α), then

Let f(x) = logₑ(sinx), (0 < x < π) and g(x) = sin⁻¹(e⁻ˣ), (x ≥ 0). If α is a positive real number such that a = (fog)’(α) and b = (fog)(α), then(A) aα² + bα – a = 2α²✓✓

(B) aα² – bα – a = 0

(B) aα² – bα – a = 0(C) aα² – bα – a = 1

(B) aα² – bα – a = 0(C) aα² – bα – a = 1(D) aα² + bα + a = 0

Answer 2

Answer:

A. will be correct answers

Step-by-step explanation:

hope the answer will help you