Math, asked by Suzuka11222, 8 months ago

Let f(x) = min{2x2, 52 − 5x}, where x is any positive real number. Then the maximum possible value of f(x) is

Answers

Answered by Anonymous
4

Answer:

Step-by-step explanation:

f(x) = min{2x2, 52 − 5x}

The maximum possible value of this function is attained when  

2x2 = 52 − 5x

2x2 + 5x − 52 = 0

(2x + 13)(x − 4) = 0

=> x = −13/2 or x = 4

Since x has to be positive integer, you can discard the case when x = −13/2.

So, x = 4 is the point at which the function attains the maximum value.

Putting x = 4 in the original function,

2x2 = 32

The maximum value of f(x) = 32.

The correct answer is 32.

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