Let f(x) = min{2x2, 52 − 5x}, where x is any positive real number. Then the maximum possible value of f(x) is
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Answer:
Step-by-step explanation:
f(x) = min{2x2, 52 − 5x}
The maximum possible value of this function is attained when
2x2 = 52 − 5x
2x2 + 5x − 52 = 0
(2x + 13)(x − 4) = 0
=> x = −13/2 or x = 4
Since x has to be positive integer, you can discard the case when x = −13/2.
So, x = 4 is the point at which the function attains the maximum value.
Putting x = 4 in the original function,
2x2 = 32
The maximum value of f(x) = 32.
The correct answer is 32.
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