Question

Let f(x)=x^2-1 .find fof &fofof

Answer 1

I THINK YOU ASKED FOR ROOTS

Answer:

1 , -1

Step-by-step explanation:

${x}^{2} - 1 \\ (x + 1)(x - 1) = 0 \\ x + 1 = 0 \: \: x - 1 = 0 \\ x = - 1 \: \: x = 1$

THE ROOTS OF f(x)=x^2-1are 1 and-1

Answer 2

sol:

f(x) = x²-1

fof = f(x²-1) = ( x²-1)²

= x⁴-2x²+1-1

( cancel one by one)

(a-b)²=a²-2ab+b²

fof = 2⁴-2x²

Answer : fof = 2⁴- 2x²

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