Question

Let f(x)=x^2 - 6x +14.
Find the critical point c of f(x) and compute f(c).
The critical point c is =
The value of f(c) = 0
Compute the value of f(x) at the endpoints of the interval [0,6].
f(0) =
$(6) =
Determine the min and max of f(x) on [0,6].
Minimum value
Maximum value
Find the extreme values of f(c) on (0,1
Minimum value
Maximum value​

Answer 1

Answer:

f(0)=14

f(6)=14

f¹(c)=0

c=3

Step-by-step explanation:

f(x)=x²-6x+14

f(0)=0²-6*0+14=0-0+14=14

f(6)=6²-6*6+14=36-36+14=0+14=14

diff. w.r.t. x

f'(x) = 2x-6

f'(c) = 2c-6

for f'(c)=0

2c-6=0

c=6/2

c=3