Question

let f (x)= x^(2)+x then write f(y+1)​

Answer 1

Answer:

$f(x) = {x}^{2} + x \\ f(y + 1) = ({y + 1})^{2} + y + 1 \\ {y}^{2} + 1 + 2y + y + 1 = {y}^{2} + 3y + 2 \: ans$