Question

Let G be a group of order 28, then

Answer 1

Step-by-step explanation:

Prove that a group of order 28 has a normal subgroup of order 7.

How can I prove this without using Sylow's theorem?

I know by Cauchy’s theorem, there exists an x∈Gx∈G with order 7, now I just need to prove it has a normal subgroup.