Let G be the cyclic group generated by an element a of order 30. What is the order of a 18?
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Answer :
Here, o(a) = 30
Now, gcd(18, 30) = 6
∴ o(a^18) = 30/gcd(18, 30)
= 30/6
= 5
#MarkAsBrainliest
Here, o(a) = 30
Now, gcd(18, 30) = 6
∴ o(a^18) = 30/gcd(18, 30)
= 30/6
= 5
#MarkAsBrainliest
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0
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