Let m=(313)4 and n=(322)4 . Find the base 4 expansion of m+n.
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12
Given that,
m = (313)₄
n = (322)₄
Now,
m = (313)₄
= [ (3 × 4²) + (1 × 4¹) + (3 × 4⁰) ]₁₀
= [ (3 × 16) + (1 × 4) + (3 × 1) ]₁₀
= (48 + 4 + 3)₁₀
= (55)₁₀
and
n = (322)₄
= [ (3 × 4²) + (2 × 4¹) + (2 × 4⁰) ]₁₀
= [ (3 × 16) + (2 × 4) + (2 × 1) ]₁₀
= (48 + 8 + 2)₁₀
= (54)₁₀
Now, m + n
= (313)₄ + (322)₄
= (55)₁₀ + (54)₁₀
= (99)₁₀
Now,
4 | 99
--------
4 | 24 ------> remainder = 3
--------
4 | 6 --------> remainder = 0
-------
4 | 1 ---------> remainder = 2
So, (99)₁₀ = (1203)₄
Hence, m + n
= (313)₄ + (322)₄
= (1203)₄
#
Answered by
0
Answer:
first convert (313) into base of 4 = 3*4(2) its 4 ka square + 1*4(1) + 3*4(0)=55
now for second (322) into base of 4 = 3*4(2) its 4 ka square + 2*4(1) + 2*4(0)=58
now we will add 55+58=113
now again convert (113) base of 4 = Answer
1*4(2)+1*4(1)+3*4(0)=1301
calculation if u do mistake for referencer
1) 3*4(2) =48
2) 1*4(1) =4
3) 3*4(0) =3
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total 55
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