Question

let m be the midpoint and l be the lower class limit of a class interval in a continuous frequency distribution. the upper class limit is ?​

Answer 1

$Given \: lower \: class \: limit \: of \: a \:class=l$

$Let \: Upper \: class \: limit \: of \: the\:class=u$

$Mid \:point = m$ [/tex]

/* we know that */

$\boxed{\pink{ \frac{ u + l }{2} = m }}$

$\implies u + l = 2m$

$\implies u = 2m - l$

Therefore.,

$\red{ Upper \:class \: limit } \green { = 2m - l }$

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