Question

let M denotes the mass of earth and let R denotes it's radius.The ratio of g/G at earth surface is

Answer 1

Explanation:

Gravity at the surface of earth g=R2GM

Gg=R2M.

Answer 2

We know that:

$g = \frac{Gm}{ {r}^{2} } \\ \\ \therefore \: \frac{g}{G} = \frac{ \cancel{G}m}{ \frac{ {r}^{2} } { \cancel{G}} } \\ \\ = > \fbox{ \frac{g}{G} = \frac{m}{ {r}^{2} }}$