Question

let me answer with explanation

Answer 1

sin15degree= root3-1/2root2 tan75degree=2+root3

Answer 2

(1) sin 15°=sin (60-45)
apply formula sin (a-b)
sinA.cosB-cosA.sinB

=(sin 60. cos45)-(cos 60. sin45)
=(ROOT 3/2×1/root2)-(1/2.1/root2)



$( \sqrt{3} \div 2 \times 1 \div \sqrt{2} ) - 1 \div 2 \times \sqrt{2}$

$( \sqrt{3} \div 2 \sqrt{2} ) - (\sqrt{2} \div 2)$
take L.C.M