Question

Let N=5ab42ab. If N is exactly divisible by 180,
then the sum of the digits in N is?​

Answer 1

Answer:

25 ya

Step-by-step explanation:

easy question it is very simple we should take of the 2 from 42 and we should multiple the 5 and 4 and the answer will be 25

Answer 2

Answer:

27

Step-by-step explanation:

Factors of 180 are

180=2^2*3^2*5 = 4*9*5

As N =5ab42ab is divisible by 180 so it should be divisible by factors of 180.  

N is divisible byb  5 and 4, so unit digit=0 hence b=0….(1)

N is divisible by 4 so its last 2 digit no should be divisible by 4.

20 , 40, 60, 80 are divisible by 4.

so p=0,4, 6or 8…………….(2)  

Now N is also divisible by 3 so sum of its digits must be divisible by 3  

Or 11+2a should be divisible by 3  

for p=2 ,11+2a=11+4=15 is not divisible by 3

for p=4 ,11+2a=11+8=19 is not divisible by 3

for p=6 ,11+2a=11+12=23 is not divisible by 3

for p=8 ,11+2a=11+16=27 is  divisible by 3

Thus a =8 is correct option

Hence, the number is '5804280'

So sum of the digits= 5+8+0+4+2+8+0 = 27