Question

Let n be an integer greater than 1 prove that 3^n is the sum of three consecutive integers

Answer 1

3^n = 3^3 x 3^(n-3)
 let 3^(n-3) = k

then,
         3^n = 27k = 9k + 9k + 9k
                = (9k+1) + 9k +(9k-1)

hence proved.

thanking you
pranay kamal