Question

let n be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case .the sum of digits in n is ?​

Answer 1

Step-by-step explanation:

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: [A]. = H.C.F. of 3360, 2240 and 5600 = 1120.