Question

let n be three digit no. such that n= sum of the squares of the squares of the digits of n. the number of such n is

Answer 1

$(text) \huge{dear friend}$
As the last digit of n^2 is 4 , then last digit of n is either 2 or 8 .

If we consider the last digit as 2 , then the digit before 4 can't be a odd number (as 5). It must be a even number ( it is a sum of the two same numbers, you can check this by taking any three digit ending with 2)

If we consider that last digit is 8 , then also the digit before 4 is a even number , as it is sun the of two same numbers + 6 .

So there is no value for n .

Answer 2

Step-by-step explanation:

As the last digit of n^2 is 4, then last digit of n is either 2 or 8.

If we consider the last digit as 2, then the digit before 4 can't be a odd number (as 5). It must be a even number ( it is a sum of the two same numbers, you can check this by taking any three digit ending with 2)

If we consider that last digit is 8, then also the digit before 4 is a even number, as it is sun the of two same numbers + 6.

So there is no value for n.