let n is the gretest number that will be divide 1305, 4665 and 6905 leaving the same reminder in each case. that sum of digit in n is
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Answer ◆ 4
Let remainder is X
So 1305-X is divisible by N
Similarly
4665-X and 6905 -X are divisible by N.
Now
(6905 -X) - ( 4665-X) = 2240
is divisible by N
Example - if 49 is divisible by 7
————— 28 is divisible by 7
———- then 49–28 =21 is divisible by 7
Similarly
(4665-X)-(1305-X) = 3360
HCF of 2240 and 3360 is 1120
So Value of N is 1120
Sum of digits of N is 4 (1+1+2+0)
∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆∆
Verification
1120) 1305( 1
——-1120
———185
●●●●●●●●●●●●●●●●●●●●●●●●●●●●
1120)4665( 4
——4480
———185
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
1120)6905(6
——-6720
———185
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