Chemistry, asked by asmaul5445, 11 months ago

Let np and ne be the numbers of holes and conduction electrons in an extrinsic semiconductor.
(a) np > ne
(b) np = ne
(c) np < ne
(d) np ≠ ne

Answers

Answered by stefangonzalez246
1

In an extrinsic semiconductor,  np ≠ ne.

Explanation:

Extrinsic semiconductor

  • Which an impurity controls the rate in addition to make it conductive for a semiconductor is called extrinsic semiconductor.
  • There are two types of semiconductors p type and n type semiconductor.
  • The semiconductor which results in doping, for negative n-type semiconductor that has an extra electrons and one fewer electrons for positive p type semiconductor.
  • Moderately and lightly the semiconductors are doped.
  • In addition of trivalent impurities which are made from extrinsic semiconductor are called p type.
  • 'Number of holes is more than number of electrons' in p type semiconductor.
  • In addition of pentavalent impurities which are made from extrinsic semiconductor are called n type.
  • 'Number of electrons is more than number of electrons' in n type semiconductor.
  • Hence, the number of electrons and holes are not equal.

To learn more;

  1. https://brainly.in/question/11330308
  2. https://brainly.in/question/2847627
Answered by shilpa85475
1

Let np and ne be the numbers of holes and conduction electrons in an extrinsic semiconductor is np ≠ ne. From the question, it is understood that ne and np are the numbers of conduction electrons and holes in an extrinsic semiconductor.

Explanation:

The formation of the extrinsic semiconductor is either by doping a p-type material or doping an n-type material with a pure semiconductor.

So, this will have more number of electrons if the n-type doping material is used, or more number of holes if p-type doping material is used.

Similar questions