Let P and Q be the points of trisection of the line segment joining the points A(2, -2) and B(-7, 4)
such that P is nearer to A. Find the coordinates of P and Q.
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Answer:
P(-1,0),Q(-4,2)
Step-by-step explanation:
given A(2,-2); B(-7,4)
ratio m:n=1:2
using section formula
(x,y)=(mx2+nx1/m+n),(my2+ny1/m+n)
co ordinates of point P
=(1(-7)+2(2)/1+2),(1(4)+2(-2)/1+2)
=(-7+4/3),(4-4/3)
=(-3/3,0/3)=(-1,0)
co ordinates of points
=(2(-7)+1(2)/2+1),(2(4)+1(-2)/2+1)
=(-14+2/3,8-2/3)
=(-12/3,6/3) =(-4,2)
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