Question

Let P be a point inside a triangle ABC with angle ABC = 90O. Let P1 and P2 be the images of P under reflection in AB and BC respectively. The distance between the circumcenters of triangles ABC and P1 PP2 is

Answer 1

Thank you for asking this question. The options for this question are missing. Here are the missing options:

a)   AB/2                    

b) (AP+BP+CP)/3        

c)  AC/2                      

d) (AB/BC/AC)/2

Answer:

In order to find the answer for this question we will find the circumcenters of the triangle ABC and P1 PP2 and then finally we will find out the distance between them.

Attached is the image which will be formed when we will solve this question.

The correct answer for this question is option B: (AP+BP+CP)/3

If there is any confusion please leave a comment below.