Question

Let p(x) = 3x2 + 6x + 1. Find p(0), p(1), p(-1), p(2)

Answer 1

Answer:

1.1 p(0)

p(x) = 3x² + 6x + 1

= 3(0)² + 6(0) + 1

= 0 +0 +1

= 0

1.2 p(1)

p(x) = 3x² + 6x +1

3(1)² + 6(1) +1

= 3 + 6 +1

= 10

1.3 p(-1)

p(x) = 3x² + 6x + 1

3(-1)² + 6(-1) +1

3 + (-6) +1

3+ 1

4

1.4 p(2)

p(x) = 3x² + 6x +1

= 3(2)² + 6(2) +1

= 12 + 12 + 1

= 25