Question

Let P(x) = ax2 + bx + 8 is a quadratic polynomial. If the minimum value of P(x) is 6 when
x = 2, then 4a + 3b is
(A) 4
(B)
-6
(C) -4
(D) 6​

Answer 1

Answer:

3

Step-by-step explanation:

1) P(x) = ax² + bx + 8.

2) Therefore, If P(x) = 6

3) And, x = 2.

4) Therefore, a(2)² + b(2) + 8 = 6

5) 4a + 2b = -2.

6) 2a + b = -1

7) 2a = b - 1

8) b - 1 + b = -1

9) b = 1

10) 2a = 1 - 1

11) a = 0

12) Therefore 4(0) + 3(1) = 3

Answer 2

Step-by-step explanation:

Now, Since you know the values of a and b . you can go ahead and find 4a+3b

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