let p(x)= x² - 1/2 then find p(x) (-x/2)
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Given, P(x 2 +1)={P(x 2 )} 2 +1 ...(1)
Given P(0)=0 Put x=0 in (1)
⇒P(1)=P(0) 2+1⇒P(1)=1
Also, put x=1 in (1)⇒P(2)=2
Also, since, P(x) is a polynomial so we have P(x)=x⇒P ′ (x)=1
P ′ (0)=1
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