Question

let p(x)= x²-4x+3 .find the value of p(0), p(1), p(2) , p(3) , and obtain zeroes of the polynomial p(x)​

Answer 1

Answer:

p(0)=3

p(1)=0

p(2)=-1

p(3)=0

hope it helps you

tq for following me

Answer 2

Step-by-step explanation:

p(x)=x²- 4x+3

p(0)=0²-4×0+3

=0-0+3 = 3

p(1)=1²-4×1+3

=1-4+3 = 0

p(2)=2²-4×2+3

=4-8+3 = -1

p(3)=3²-4×3+3

=9-12+3 = 0