Question

Let R be the set of real numbers. If f(x) = x2 and g(x) = 2x + 1, then fog(x) is equal to
(a) 2x + 1, (b) 2x2 + 1, (c) (2x + 1)2, (d) None of these

please help me ...​

Answer 1

Answer: (c) (2x+1)^2

Step-by-step explanation:

$f(x) = x^2$ $and$  $g(x) = 2x+1$

$fog(x) = f(g(x)) = f(2x+1) \\now \ put \ 2x+1 in \ place \ of \ x \ in \ f(x)\\then,\ fog(x) = (2x+1)^2$

Answer 2

$\sf f \circ g(x) = {(2x + 1)}^{2}$

Given :

Let R be the set of real numbers.

f(x) = x² and g(x) = 2x + 1

To find :

$\sf f \circ g(x)$ is equal to

(a) 2x + 1

(b) 2x² + 1

(c) (2x + 1)²

(d) None of these

Solution :

Step 1 of 2 :

Write down the given functions

Here it is given that R be the set of real numbers.

f(x) = x² and g(x) = 2x + 1

Step 2 of 2 :

Find $\sf f \circ g(x)$

$\sf f \circ g(x)$

$\sf = f ( g(x))$

$\sf = f ( 2x + 1)$

$\sf = {( 2x + 1) }^{2}$

Hence the correct option is (c) (2x + 1)²

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